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4u^2-27u-7=0
a = 4; b = -27; c = -7;
Δ = b2-4ac
Δ = -272-4·4·(-7)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-29}{2*4}=\frac{-2}{8} =-1/4 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+29}{2*4}=\frac{56}{8} =7 $
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